Algorithmsdp interval partitioning
Partitioning DP on Intervals and Segments
TT
Testlaa Team
May 14, 2026•1 min read
Partition DP splits sequences into segments with a cost per segment—palindrome partitioning, burst balloons style interval DP dp[i][j].
Why this shows up in the real world
Text line breaking minimizes badness per line. DNA segment labeling.
Core idea (explained for students)
Try all split points k between i..j-1: dp[i][j]=min_k cost(i,k)+dp[k+1][j].
Try this in Python
def min_cut_palindrome(s: str) -> int:
n = len(s)
is_pal = [[False] * n for _ in range(n)]
for i in range(n - 1, -1, -1):
for j in range(i, n):
if s[i] == s[j] and (j - i < 2 or is_pal[i + 1][j - 1]):
is_pal[i][j] = True
dp = [0] * (n + 1)
for i in range(n - 1, -1, -1):
dp[i] = n - i
for j in range(i, n):
if is_pal[i][j]:
dp[i] = min(dp[i], 1 + dp[j + 1])
return dp[0] - 1
print(min_cut_palindrome('aab'))
Common mistakes
- O(n^3) too slow for large n without pruning.
- Off-by-one on inclusive ranges.
Key takeaways
- Prefix preprocessing (is palindrome[i:j]) turns inner checks O(1).
Tags:
Dynamic programmingPythonStudents
