Algorithmspath maximum query in tree
Path Maximum Query on Trees
TT
Testlaa Team
May 15, 2026•2 min read
Path maximum on a tree walks from u to v using LCA + HLD (or link-cut tree advanced)—segment tree stores max on each chain.
Why this shows up in the real world
Time-series dashboards, game leaderboards, and competitive programming interval problems all need fast answers on changing arrays.
Core idea (explained for students)
Query max on upward segments until chains meet; compare with LCA segment if needed.
Try this in Python
class SegTreeMin:
INF = 10**18
def __init__(self, arr: list[int]) -> None:
self.n = len(arr)
self.size = 1
while self.size < self.n:
self.size *= 2
self.t = [self.INF] * (2 * self.size)
for i, x in enumerate(arr):
self.t[self.size + i] = x
for i in range(self.size - 1, 0, -1):
self.t[i] = min(self.t[2 * i], self.t[2 * i + 1])
def query(self, l: int, r: int) -> int:
l += self.size
r += self.size
ans = self.INF
while l <= r:
if l % 2 == 1:
ans = min(ans, self.t[l])
l += 1
if r % 2 == 0:
ans = min(ans, self.t[r])
r -= 1
l //= 2
r //= 2
return ans
print(SegTreeMin([4, 2, 7, 1, 9]).query(0, 3))
Common mistakes
- Treating tree as array without HLD.
- Off-by-one on depth/parent arrays.
Key takeaways
- Learn LCA (binary lifting) before HLD path max.
- Same pattern for path sum with different monoid.
Tags:
Segment tree & range queriesPythonStudents
